Respuesta :

Medunno13

Answer: 196

Step-by-step explanation:

By the geometric mean theorem,

[tex]\frac{96}{40\sqrt{6}}=\frac{40\sqrt{6}}{x-96}[/tex]

Solving for x,

[tex](40\sqrt{6})^{2}=96(x-96)\\9600=96(x-96)\\100=x-96\\x=196[/tex]

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