Moles of Br- is mathematically given as
moles of Br-=28*10^{2}
Option A
Moles of Br-
The chemical reaction is
MgBr2 ----> Mg+2 + 2Br-
Let 940mL be present
Generally the equation for the Morarity is mathematically given as
molarity = moles / volume (L)
Therefore
1.5 = moles / 940 x 10-3
moles = 1400
Hence, moles of MgBr2 is 1.0125
Therefore
moles of Br- = 2 x moles of MgBr2
moles of Br- = 2 x 1400
moles of Br-=28*10^{2}
Mor on Molecules
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