Answer:
[tex]m=-\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{2-6}{13-1}\\ \\m=\frac{-4}{12}\\ \\m=-\frac{1}{3}[/tex]
Therefore, the slope of the line that passes through the points [tex](x_1,y_1)\rightarrow(1,6)[/tex] and [tex](x_2,y_2)\rightarrow(13,2)[/tex] is [tex]m=-\frac{1}{3}[/tex]
