sisnsjakn sisnsjakn
  • 19-03-2022
  • Mathematics
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Evaluate geometric series

Evaluate geometric series class=

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gurbaazuppal2010
gurbaazuppal2010 gurbaazuppal2010
  • 19-03-2022
Sn=a1(1-rn)1-r,r=1 is answer
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algebraic12 algebraic12
  • 19-03-2022

Answer:

7.5

Step-by-step explanation:

Sum of a geometric series,

[tex] \frac{a _{1}(1 - r {}^{n} ) }{1 - r} [/tex]

Where a1 is the first term, R is the common ratio, n is the number of terms.

a1 is 5

r is 1/3

n is 10.

[tex] \frac{5(1 - ( \frac{1}{3} ){}^{10} ) }{ \frac{2}{3} } [/tex]

Which is about

7.50

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