Answer:
[tex]\boxed{\tt x=3,2}[/tex]
Step-by-step explanation:
[tex]\tt x^2-5x+6=0[/tex]
Find two numbers that add up to -5 and multiply to 6: (-6 and -2)
Now, rewrite the expression:
[tex]\tt (x-3)(x-2)[/tex]
[tex]\tt (x-3)(x-2)=0[/tex]
Now, Solve for x:
1)
[tex]\tt x-3=0[/tex]
[tex]\tt x-3+3=0+3[/tex]
[tex]\boxed{\tt x=3}[/tex]
2)
[tex]\tt x-2=0[/tex]
[tex]\tt x-2+2=0+2[/tex]
[tex]\boxed{\tt x=2}[/tex]
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