Answer:
[tex]\huge\boxed{\sf 6x^2-x+16}[/tex]
Step-by-step explanation:
[tex]= (2x-3)(3x+4)\\\\Expand\\\\= 2x(3x+4)-3(3x+4)\\\\Distribute\\\\= 6x^2+8x-9x+16\\\\= 6x^2-x+16\\\\\rule[225]{225}{2}[/tex]
6x²-x-12
(2x-3)(3x+4)
2x(3x+4) -3(3x+4)
6x²+8x-9x-12
