Yoyoyoyocv Yoyoyoyocv
  • 19-04-2022
  • Mathematics
contestada

In the figure shown below, cos 0 =

In the figure shown below cos 0 class=

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loneguy
loneguy loneguy
  • 19-04-2022

[tex]\cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\ \\\\~~~~~~~=\dfrac{3}{\sqrt{3^2 +2^2}}~~~~~~~;[\text{Pythagorean theorem.}]\\\\\\~~~~~~~=\dfrac{3}{\sqrt{9+4}}\\\\\\~~~~~~~=\dfrac{3}{\sqrt{13}}[/tex]

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