Answer:
D
Step-by-step explanation:
Quadratic formula: [tex]\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]2x^2- 12x + 13 = 0[/tex]
[tex]x=\frac{-(-12)+-\sqrt{(-12)^2-4(2)(13)} }{2(2)}[/tex]
[tex]x=\frac{12+-\sqrt{144-104} }{4}[/tex]
[tex]x=\frac{12+-\sqrt{40} }{4}[/tex]
[tex]x=\frac{12+-2\sqrt{10}}{4}[/tex]
[tex]x=\frac{6+-\sqrt{10}}{2}[/tex]
I hope this helps!
