Answer:
x ≈ 45.6°
Step-by-step explanation:
using the Cosine rule in the triangle
cos x = [tex]\frac{8^2+15^2-11^2}{2(8)(15)}[/tex] = [tex]\frac{64+225-121}{240}[/tex] = [tex]\frac{168}{240}[/tex] , then
x = [tex]cos^{-1}[/tex] ( [tex]\frac{168}{240}[/tex] ) ≈ 45.6° ( to 1 dec. place )
