ecallanan3718 ecallanan3718

19-05-2022
Chemistry

contestada

How many moles is 8.7 x 1027 atoms of Helium?

Respuesta :

evgeniylevi evgeniylevi

19-05-2022

Answer:

14500.

Explanation:

1) Avlgadro's number is 6.022*10²³;

2) 1 mol is 6.022*10²³ atoms of Hellium, then 8.7*10²⁷ atoms is

[tex]3) \ \frac{87*10^{26}}{6*10^{23}}=14.5*10^3=14500[moles].[/tex]

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