I'm assuming the given log equation is [tex]\log_{\text{x}}(49) = \text{x}[/tex]
If so, then the exponential form is [tex]\text{x}^{\text{x}} = 49[/tex]
This is because the general form [tex]\log_{\text{b}}(\text{x}) = \text{y}[/tex] transforms into [tex]\text{y} = \text{b}^{\text{x}}[/tex]
For both equations, the 'b' is the base.
