troubleman22208 troubleman22208

20-06-2022
Mathematics

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Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores

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20-06-2022

Answer:

Mean deviation of 80, 88, 93, 95 is 5

Step-by-step explanation:

Step 1: find the mean

Mean = Sum of items/ Number of items

Mean = 80+88+93+95 = 356

Mean = 356 / 4 = 89

Step 2: find the mean deviation

Mean Deviation = ∑i = 0n |xi − μ| / N

Mean Deviation = | (89-80) + (89-88) + (89-93) + (89-95) | /4

Mean Deviation = 5

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