The radius of the circular cross-section of the can of soup is; 3.4cm.
What is the radius of the can of soup?
Since, the can has a height of 10cm and the volume of the can is 363cm³, it follows that the area of the circular cross-section can be evaluated as;
A = 363/10 = 36.3cm²
Hence, it follows that the radius can be evaluated as follows;
36.3 = 3.14 × r²
r² = 36.3/3.14
r² = 11.56
r = 3.4cm
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