18.26 g of Al can be recovered.
Calculation:
The equation that follows is:
2Al₂O₃ → 2Al + 3O₂
The atomic mass of Al = 27 g
The molecular mass of Al₂O₃ = 102 g
From the stoichiometric equation, 102g of Al₂O₃ yields 54 g of Al
Therefore,
34.5 g of Al₂O₃ will give = [tex]\frac{54 (34.5)}{102}[/tex]
= 18.26 g
Learn more about stoichiometric calculations here:
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