nabiusrogers110 nabiusrogers110
  • 20-07-2022
  • Mathematics
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Need help with this one

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cygnusabc00
cygnusabc00 cygnusabc00
  • 20-07-2022

Answer:

The answer is a.2x/9

Step-by-step explanation:

[tex] \frac{x {}^{2} }{3y} \div \frac{3x}{2y} \\ \frac{x {}^{2} }{3y} \times \frac{2y}{3x} \\ \frac{x {}^{2} }{3} \times \frac{2}{3x} \\ \frac{x}{3} \times \frac{2}{3} = \frac{2x}{9} [/tex]

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