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A man heats a balloon in the oven. The balloon initially measures 0.402 L with a temperature of 20.0°C, what will the volume of the balloon be after he heats it to a temperature of 250.0°C?

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samueladesida43

The volume of the balloon after he heats it to a temperature of 250.0°C is 0.718L.

How to calculate volume?

The volume of a balloon at a particular temperature can be calculated by using the Charles law formula as follows:

V1/T1 = V2/T2

Where;

  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

According to this question, a man heats a balloon in the oven. The balloon initially measures 0.402 L with a temperature of 20.0°C. However, the volume of the balloon after he heats it to a temperature of 250.0°C can be calculated as follows:

  • T1 = 20°C + 273 = 293K
  • T2 = 250°C + 273 = 523K

0.402/293 = V2/523

523 × 0.402 = 293V2

210.25 = 293V2

V2 = 210.25/293

V2 = 0.718L

Therefore, the volume of the balloon after he heats it to a temperature of 250.0°C is 0.718L.

Learn more about volume at: https://brainly.com/question/24189159

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