Seudónimo
Seudónimo
22-02-2017
Mathematics
contestada
tan\theta =2sin\theta
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jdoe0001
jdoe0001
22-02-2017
[tex]\bf tan(\theta)=2sin(\theta)\qquad \begin{cases} tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad thus \end{cases}\\\\ -----------------------------\\\\ \cfrac{sin(\theta)}{cos(\theta)}=2sin(\theta)\implies \cfrac{sin(\theta)}{2sin(\theta)}=cos(\theta)\implies \cfrac{1}{2}=cos(\theta) \\\\\\ \textit{now, taking }cos^{-1}\textit{ to both sides} \\\\ cos^{-1}\left( \cfrac{1}{2} \right)=cos^{-1}[cos(\theta)]\implies cos^{-1}\left( \cfrac{1}{2} \right)=\measuredangle \theta[/tex]
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