terrylsaffold
terrylsaffold
20-03-2017
Mathematics
contestada
evaluate h(x)=-x2+1 for x=3
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colella51
colella51
20-03-2017
h(3) = -3*2 + 1 = -5
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apologiabiology
apologiabiology
20-03-2017
h(3), jsut subsitute 3 for x
h(3)=-(3)^2+1
h(3)=-(9)+1
h(3)=-9+1
h(3)=-8
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