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A rocket was is shot vertically into the air. Its height,h.at any time,t,in seconds,can be modeled by the equation h=-16t^2 + 184t. Determine algebraically ,the number of seconds it will take the rocket to reach a height of 529 feet.

Respuesta :

1 foot =0.305m
529 feet =xm
cross-multiply
x=529×0.305
x=161.35m.
h=dv/dt=-16×2t^2-1+184t^1-1
dv/dt=-32t+184 ............