I will assume that is half of a sphere although it looks squashed :P
The surface area of a sphere is 4pr^2 and we only have half of the sphere so we have:
2pr^2 for the hemisphere area....
The surface area of the cylinder is 2prh+2pr^2 however there is only one base so our cylinder area is: 2prh+pr^2
So our total surface area is:
A=2pr^2+pr^2+2prh
A=3pr^2+2prh, given that r=9 and h=12...
A=3p81+2p9(12)
A=459p ft^2
A≈1441.0 ft^2 (to nearest tenth of a square foot)
