Respuesta :

Given: KL is a tangent to the circle.
LM is another tangent to the circle.

We can use the tangent meeting at an external point theorem.
Theorem: The tangent segments to a circle from an external point are equal.

Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.

4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5

Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18

Thus, LM = KL = 18 units.

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