so hmm notice the picture below
running a segment from the right-angle perpendicular to the opposite side, gives three similar triangles, one small, a medium and a large one
now, using proportions, you can simply [tex]\bf \textit{using proportions}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{10}{6}=\cfrac{x}{10}[/tex]
and solve for "x"
