Answer:
Factored form is of (6y² - 20y + 6).
Step-by-step explanation:
We have to find the expression of which factored form is 2(3y -1)(y -3).
We will further simplify these factors to get the original expression.
2(3y -1)(y - 3) = 2[3y(y - 3) - 1(y -3)]
= 2[ 3y² - 9y - y + 3]
= 2(3y² - 10y + 3)
= 6y² - 20y + 6
Therefore the factored form is of 6y² - 20y + 6.
