The length of a rectangle is six times its width.
If the area of the rectangle is 600yd^2, find its perimeter.

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18-05-2015
Mathematics

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The length of a rectangle is six times its width.
If the area of the rectangle is 600yd^2, find its perimeter.

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darth666 darth666 · Answer 1 · 2015-05-18T21:21:05+02:00

darth666 darth666

18-05-2015

rectangle area = a*b
perimeter = 2(a+b)

a - lenght
b - width

a = 6b

a*b=600
6b*b=600
[tex]6b^2=600[/tex]
[tex]b^2=100[/tex]
[tex]b=\sqrt{100}[/tex]
b=10
a = 6*10 = 60
Perimeter = 2(a+b)=2(60+10)=2*70=140 yd

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The length of a rectangle is six times its width. If the area of the rectangle is 600yd^2, find its perimeter.

Respuesta :

Otras preguntas

The length of a rectangle is six times its width.
If the area of the rectangle is 600yd^2, find its perimeter.