Respuesta :

geerky42
Let u = x², then we would have u² + 5u - 6 = 0

From here, we can factor it and get us (u-1)(u+6) = 0

So our solution for u is u = -6 or 1.

Now substitute u back to x².

x² = -6 or 1

x = ±√(-6) or ±√1

Since ±√(-6) is not real number, we ignore it.

Which leave us x = ±√1 = ±1

So our real solution is x = -1 or 1.

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