Answer:
[tex]\dfrac{9\pi+120}{4}[/tex]
Step-by-step explanation:
[tex]\text{Solution: }\\\text{Area of composite figure = Area of two rectangles + Area of quarter circle}\\\text{}\qquad\qquad\qquad\qquad\qquad\quad\text{}=lb+lb+\dfrac{1}{4}\pi r^2\\\text{}\qquad\qquad\qquad\qquad\qquad\quad\text{}=5\times3+5\times3+\dfrac{1}{4}\pi (3)^2=30+\dfrac{9}{4}\pi\\[/tex]
[tex]\therefore\ \text{Area of composite figure = }\dfrac{9\pi+120}{4}[/tex]
