To draw the graph of (y = -x^2 + 4x - 5), first, let's find the vertex of the parabola. The vertex of a parabola in the form (y = ax^2 + bx + c) is given by the point ((h, k)), where (h = \frac{-b}{2a}) and (k = f(h)).In this case, (a = -1), (b = 4), and (c = -5). So, we have:
