To be able to solve this problem, we must be given the
balanced chemical equation:
3A + 5B + 1C ---> 2D + 1E
Our reactant A is called the limiting reactant because it
is limited in amount which is only 6 moles. So we based our calculation on that
reactant alone.
From stoichiometry, we have 1 mole of E for every 3 moles
of A, therefore:
moles E = 6 moles A * (1 mole E / 3 moles A)
moles E = 2 moles
