[tex]8\times1=8 \ \textless \ 52\\8\times2=16 \ \textless \ 52\\8\times3=24 \ \textless \ 52\\8\times4=32 \ \textless \ 52\\8\times5=40 \ \textless \ 52\\\boxed{ \begin{array}{ccc}8\times6=48 \ \textless \ 52\\8\times7=56 \ \textgreater \ 52\end{array}}\\\\52-48=4\\\\therefore\\\\\huge\boxed{52:8=6\ and\ R=4}[/tex]
