Respuesta :
In the problem instead of using LW, let us use L alone.
h is the height from the bottom of the window to the position where from which the pot was dropped
L = (Vb)t - 0.5gt^2 or
(Vb) = (L/t) + 0.5gt-----------------------------------...
Also (Vb) ^2 =2gh,
Hence
2gh = [(L/t) + 0.5gt] ^2
h = [(L/t) + 0.5gt] ^2/ 2g. This is the needed equaation.
This can be modified as
h = (L^2/2gt^2) + (L/2) + (gt^2/8)
======================================...
b)
V-ground^2 - Vb^2 = 2g Hb
V-ground^2 = 2g (h_ total) = 2g Hb + Vb^2
2g ( h_ total) = 2g Hb + Vb^2
( h_ total) = Hb + Vb^2/2g
======================================...
c)
From 1 (Vb) = (L/t) + 0.5gt
The bottom of window is at a height Hb above the ground
V-ground^2 - Vb^2 = 2g Hb
V-ground^2 = 2g Hb + Vb^2
Substituting for Vb, we get the required equation.