Answer:
ΔKML Option C
Step-by-step explanation:
Given right triangle is ΔJKL
Where ∠JKL = 90°
Here KM is perpendicular to LJ.
In triangle ΔJKL & ΔKML
∠JKL ≅ ∠KML (both are right angle)
∠JLK ≅ ∠KLM (common angle in both the triangles)
So,
ΔJKL is similar to ΔKML.
That's the final answer.
I hope it will help you.
