Respuesta :

[tex] \frac{23a^3b^2}{69ab^3} [/tex]

You simplify out...69 and 23 (divide each for 3), a^3 and a (since you divide them, you have to subtract the exponents...3-1 = 2), b^2 and b^3 (3-2 = 1)

[tex] \frac{a^2}{3b} [/tex] (final result)

So a²/3b

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