itsdianaduh itsdianaduh
  • 19-10-2017
  • Mathematics
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jdoe0001 jdoe0001
  • 19-10-2017
[tex]\bf \begin{array}{cccll} x&171x-337778&\textit{internet users}\\ ----&-------&------\\ 2004&171(2004)-337778&4906\\ 2005&171(2005)-337778&5077\\ 2006&171(2006)-337778&5248\\ 2007&171(2007)-337778&5419\\ 2008&171(2008)-337778&5590\\ 2009&171(2009)-337778&5761\\ 2010&171(2010)-337778&5932\\ \end{array}[/tex]

now, that's using the table of values, let's do so using N = 5932

[tex]\bf N=171x-337778\implies 5932=171x-337778 \\\\\\ 5932+337778=171x\implies 343710=171x\implies \cfrac{343710}{171}=x \\\\\\ 2010=x[/tex]
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