mathmath2247
mathmath2247 mathmath2247
  • 17-01-2018
  • Mathematics
contestada

vertex and axis of symmetry f(x)=2x^2-16x-17
PLEASE HELP

Respuesta :

jessicaanilover
jessicaanilover jessicaanilover
  • 17-01-2018
The vertex is at (4, -49) and the axis of symmetry is at x= 4.

To find the vertex of this equation, use this method: [tex]( \frac{-b}{2a}) [/tex]

a=2
b=-16

This will help get your x value and the axis of symmetry. To find the y value of the vertex, insert the x value, 4 to get your y value, -49.
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