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20-07-2014
Mathematics

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if a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.

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Аноним Аноним

23-07-2014

according to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
a²/bc+b²/ca+c²/ab=3.
hence proved

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