Here, we know that [tex]volume = length * width * height[/tex], or [tex]V=lwh[/tex]. You can algebraically manipulate this to solve for [tex]h[/tex]. [tex]h= \frac{V}{lw} [/tex]. Plugging in the known information, you get [tex]h= \frac{120}{5*8} = 3 \ cm[/tex].
