Answer:
[tex]f^{-1}(x)=\sqrt{x+5}[/tex]
Step-by-step explanation:
Interchange x and y, then solve for y.
[tex]x = y^2 -5\\\\x+5=y^2\\\\\sqrt{x+5}=y\\\\f^{-1}(x)=\sqrt{x+5}[/tex]
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The attached graph shows the function f(x) and its inverse g(x). They are reflections of each other across the line y=x, as they should be.
