devinbirdwell29
devinbirdwell29 devinbirdwell29
  • 20-02-2018
  • Mathematics
contestada

Solve (x + 2 < 5) (x - 7 > -6).

{x | -6 < x < 5}
{x | x < 3 or x > 1}
{x | x < 0}

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Jr04
Jr04 Jr04
  • 26-02-2018
Solve (x + 2 < 5) (x - 7 > -6).

{x | -6 < x < 5}
{x | x < 3 or x > 1}
{x | x < 0}


[tex](x+2\ \textless \ 5) = x\ \textless \ 5-2=x\ \textless \ 3 \\ \\ \\ (x-7\ \textgreater \ -6) = x\ \textgreater \ -6+7= x\ \textgreater \ 1 \\ \\ \\ \boxed{{x | x \ \textless \ 3 \ or\ x \ \textgreater \ 1} } \quad \checkmark [/tex]
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