LBGamer
LBGamer LBGamer
  • 21-02-2018
  • Mathematics
contestada

I need help I would really thank whoever answers this for me

I need help I would really thank whoever answers this for me class=

Respuesta :

PeytonBrainly
PeytonBrainly PeytonBrainly
  • 21-02-2018
To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22
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isayin0
isayin0 isayin0
  • 21-02-2018
a.
6j - 3 for j = 4.
(6*4) - 3, 24 - 3 = 21.

b.
1/2b + 5 for b = 14
(1/2 * 14) + 5, 7 + 5 = 12

c.
8+4k for k = 3.5
8 + (3.5*4), 8 + 14 = 22

Hope this helps! You could always check these answers on a site called    Math-way (without the dash.)
Answer Link

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