we have
[tex]-4(x+3) < -2-2x[/tex]
Solve for x
Applying distributive property left side
[tex]-4x-12 < -2-2x[/tex]
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex]-4x+2x < -2+12[/tex]
[tex]-2x < 10[/tex]
Divide by [tex]2[/tex] both sides
[tex]-2x/2 < 10/2[/tex]
[tex]-x < 5[/tex] --------> [tex]x > -5[/tex]
the solution is the interval-------> (-5,∞)
therefore
the answer in the attached figure
