JamalJr
JamalJr JamalJr
  • 21-03-2018
  • Mathematics
contestada

30 POINTS + BRAINLIEST!

30 POINTS BRAINLIEST class=

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jcherry99
jcherry99 jcherry99
  • 23-03-2018
The secant tangent theorem states that the distance from (y to the tangent point x) squared = the external segment * length of the secant.
Put in plane English
YX^2 = YV * YZ
YV = 9
YZ = 9 + 19 = 28
YX^2 = 28 * 9
yX^2 = 252
YX = sqrt(252)
YX = 15.87
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nmon1943
nmon1943 nmon1943
  • 05-03-2019

The answer is 15.87.

Answer Link

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