Methanol reacts with oxygen as follow,
              CH₃OH + 3/2 O₂  →  CO₂ + 2 H₂O
Data Given;
Volume of Methanol = 60 mL
Density of Methanol = 0.787 g/mL
Calculating mass of Methanol as;
             Mass = Density × Volume
             Mass = 0.787 g/mL × 60 mL
             Mass = 47.22 g
According to equation,
             32 g of Methanol requires = 48 g (3/2 moles) of O₂
So,
        47.22 g of Methanol will require = X g of O₂
Solving for X,
                  X = (47.22 g × 48 g) ÷ 32 g
                  X = 70.83 g of O₂
