We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
[tex]\Delta V = I R[/tex]
where
[tex]\Delta V[/tex] is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance
In our problem, I=4.00 A and [tex]R=330 \omega[/tex], so the potential difference is
[tex]\Delta V = IR=(4.00 A)(330 \omega)=1320 V[/tex]
