Answer: The value of sin∠A = 36.86°.
Step-by-step explanation:
Since we have given that
AB = 5 units
AC = 4 units
BC = 3 units
So, we need to find the sine ∠A.
As we know the formula for "Sine":
[tex]\sin A=\dfrac{Opposite}{Adjacent}\\\\\sin A=\dfrac{BC}{AB}\\\\\sin A=\dfrac{3}{5}\\\\\sin A=0.6\\\\A=\sin^{-1}((0.6)\\\\A=36.86^\circ[/tex]
Hence, sin∠A = 36.86°.
