preyei
preyei preyei
  • 20-04-2018
  • Mathematics
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How do I solve this problem?

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Аноним Аноним
  • 20-04-2018
[tex]\text {Area of a triangle = } \dfrac{1}{2} \times \text{base} \times \text{height}[/tex]

[tex]\text {Area of a triangle = }[/tex]

[tex] \dfrac{1}{2} \times \dfrac{2x^2 - x - 1}{x-3} \times \dfrac{2x^2 +2x - 24}{2x + 1} [/tex]

[tex]= \dfrac{1}{2} \times \dfrac{(x-1)(2x+1)}{x-3} \times \dfrac{2(x+4)(x-3)}{2x + 1} [/tex]

[tex]= (x -1 )(x +4)[/tex]

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