kylerdt0 kylerdt0
  • 20-04-2018
  • Mathematics
contestada

how do I solve 2x-3y=-1. y=x-1

Respuesta :

prestonshelton
prestonshelton prestonshelton
  • 20-04-2018
Hello!

You can put in y for the first equation

2x - 3(x - 1) = -1

Distribute the -3

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1 to make x positive

x = 4

We can put x into the second equation to get y

y = 4 - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!
Answer Link
choixongdong
choixongdong choixongdong
  • 20-04-2018
substitute y=x-1 into 2x-3y=-1

2x-3y=-1
2x-3(x-1)=-1
2x - 3x + 3 = -1
-x = -4
x = 4

substitute x = 4 into y=x-1
y=x-1 = 4 - 1 = 3

answer
x = 4 and y = 3
Answer Link

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