Ari98
Ari98 Ari98
  • 17-02-2016
  • Mathematics
contestada

Please answer the question from the attachment.

Please answer the question from the attachment class=

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Panoyin
Panoyin Panoyin
  • 17-02-2016
[tex]\frac{y^{2} - 7y + 12}{2y^{2} - 9y + 9} = \frac{y^{2} - 4y - 3y + 12}{2y^{2} - 6y - 3y + 9} = \frac{y(y) - y(4) - 3(y) - 3(-4)}{2y(y) - 2y(3) - 3(y) - 3(-3)} = \frac{y(y - 4) - 3(y - 4)}{2y(y - 3) - 3(y - 3)} = \frac{(y - 3)(y - 4)}{(2y - 3)(y - 3)} = \frac{y - 4}{2y - 3}[/tex]
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