Answer:
i, ii, iv
Step-by-step explanation:
A Pythagorean triplet satisfies the relation:
[tex]\boxed{a^2+b^2=c^2}[/tex]
[tex]10^2+24^2=26^2\\100+576 = 676\\676 = 676[/tex]
[tex]14^2+48^2=50^2\\196+2304= 2500\\2500= 2500[/tex]
[tex]18^2+79^2=82^2\\324+6241= 6724\\6565 \neq 6724[/tex]
[tex]22^2+120^2=122^2\\484+14400 = 14884 \\14884 = 14884[/tex]
