Respuesta :

luana
[tex] \left \{ {{3x+2y=11\ \ \ \ \ \ \ } \atop {x-2y=4y\ \ | add\ 2y}} \right.\\\\ \left \{ {{3x+2y=11} \atop {x=4y+2y}} \right.\\\\substitution\ method\\\\ 3(4y+2y)+2y=11\\\\ 3*6y+2y=11\\\\ 18y+2y=11\\\\ 20y=11\ \ \ | divide\ by\ 20\\\\ y=\frac{11}{20}\\\\ x=6y=6* \frac{11}{20}=\frac{66}{20}=\frac{33}{10}\\\\ [/tex]
SlyDevito

I know this is already answered but this is the answer simplified

(4, -1/2)

This is to help those that didn't understand the first guys explanation.

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